WebAlgebra. Graph (x^2)/16+ (y^2)/36=1. x2 16 + y2 36 = 1 x 2 16 + y 2 36 = 1. Simplify each term in the equation in order to set the right side equal to 1 1. The standard form of an ellipse or hyperbola requires the right side of the equation be 1 1. x2 16 + y2 36 = 1 x 2 16 + y 2 36 = 1. This is the form of an ellipse. WebJun 15, 2016 · Vertices are (-5,0) and (5,0) and focii are (0,-4) and (0,4). The given equation, x^2/9+y^2/25=1 or x^2/3^2+y^2/5^2=1, is clearly the standard form of equation of an ellipse with center at (0,0), major axis as 5xx2=10 (at y-axis) and minor axis as 3xx2=6 (at x-axis). Clearly vertices are (-5,0) and (5,0). Eccentricity is e=sqrt(1-3^2/5^2)=sqrt ...
Ellipse and hyperbola Step-by-Step Math Problem Solver
WebFree graphing calculator instantly graphs your math problems. WebIn mathematics, a square root of a number x is a number y such that y² = x; in other words, a number y whose square (the result of multiplying the number by itself, or y ⋅ y) is x. For example, 4 and −4 are square roots of 16, because 4² = (−4)² = 16. Every nonnegative real number x has a unique nonnegative square root, called the ... how to run cli commands
Solve (x+5)^2+(y+1)^2=16 Microsoft Math Solver
WebGraph x=(y+1)^2. Step 1. Simplify . Tap for more steps... Step 1.1. Rewrite as . Step 1.2. Expand using the FOIL Method. Tap for more steps... Step 1.2.1. Apply the distributive property. Step 1.2.2. Apply the distributive property. Step 1.2.3. Apply the distributive property. Step 1.3. Simplify and combine like terms. WebSlope: − 2 5 - 2 5. y-intercept: (0,5) ( 0, 5) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Tap for more steps... x y 0 5 5 3 x y 0 5 5 3. Graph the line using the slope and the y-intercept, or the points. Slope: − 2 5 - 2 5. y-intercept: (0,5) ( 0, 5) northern redneck taxidermy